If it's not what You are looking for type in the equation solver your own equation and let us solve it.
v^2+12v-13=0
a = 1; b = 12; c = -13;
Δ = b2-4ac
Δ = 122-4·1·(-13)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-14}{2*1}=\frac{-26}{2} =-13 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+14}{2*1}=\frac{2}{2} =1 $
| -8+5x=-14+x+4+3x | | 656=-8(-2+8x) | | -9s-15=-6 | | 4x5=45 | | j^2+14j+49=0 | | 3j^2+19j+6=0 | | 3x-46=3(x+2) | | 14z-11z+2z-4z=17 | | 8j^2+15j-2=0 | | 3w-2w+w=10 | | -15=-8x-7+7x | | 2d-18=3 | | 10t+-6t-t-2t-4t=15 | | -370=10(10a-7) | | (x+3)=(3x+1) | | -15.09+r=9.085 | | 6x+3-5x-5=-2 | | 10t−6t−t−–2t−4t=15 | | 3j^2-28j+9=0 | | 12=-0.01x^2+0.7x+6 | | 19k+2k-11k-8k=14 | | 2k^2-19k+9=0 | | F(x)=-8+5x | | 0=(x^2-5x+6) | | 37=13-2x | | 11-3w+7w=-45 | | 0.0006x3-77.523x2+3E+06x-5E+10 R²=0.2349 | | -6v-15v+18v=15 | | 3(x+5)=-3x-21+4x | | 6c+4c-5c+3c-6c=12 | | x+3/7=x/4 | | -11=1-2k+4k |